Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 781: 29


$$ z_x=ye^{xy}, \quad z_y=xe^{xy}. $$

Work Step by Step

Recall that $(e^x)'=e^x$ Since $ z=e^{xy}$, then by using the chain rule, we have $$ z_x=ye^{xy}, \quad z_y=xe^{xy}. $$
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