Work Step by Step
Since $ y=1$, then we have $$ z=x^4+6x-1$$ and hence $ z_x=4x^3+6$. So the slope of the tangent line to the curve at $(1,1,6)$ is $$ z_x(1,1,6)=4+6=10$$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.