Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 780: 5


$$ f_z(2,3,1)=6.$$

Work Step by Step

Since $ f(x,y,z)=xyz $, then we have $$ f_z(x,y,z)=xy \Longrightarrow f_z(2,3,1)=2(3)=6.$$
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