Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 780: 2


$$\frac{\partial }{\partial y}(x^2+y)(x+y^4) =x+4x^2y^3+5y^4.$$

Work Step by Step

$$\frac{\partial }{\partial y}(x^2+y)(x+y^4)=(1)(x+y^4)+(x^2+y)(4y^3)\\ =x+4x^2y^3+5y^4.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.