Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 14 - Calculus of Vector-Valued Functions - 14.2 Calculus of Vector-Valued Functions - Exercises - Page 720: 38


See the proof below.

Work Step by Step

We have $$\frac{d}{dt} (a\times r)=\frac{da}{dt} \times r+a\times \frac{dr}{dt}=a\times \frac{dr}{dt}$$ since $a$ is constant, that is, $\frac{da}{dt} =0$.
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