## Calculus (3rd Edition)

$$x+z=3.$$
Since the normal vector $n$ is $\langle 1,0,1\rangle$ and, using the fact that the plane passes through $(-2,-3,5)$, the equation of the plane is given by $$(x+2)+0(y+3)+(z-5)=0\Longrightarrow x+z-3=0$$ Hence the equation is given by $$x+z=3.$$