Answer
$\langle 1,0,-1\rangle $
Work Step by Step
The normal vector of a plane in the form of
$ax+by+cz=d $
is given by:
$\vec n=\langle a,b,c\rangle $
Therefore, the normal vector of $1x+0y-1z=0$
will equal
$\vec n=\langle 1,0,-1\rangle $
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