Calculus (3rd Edition)

by Rogawski, Jon; Adams, Colin

Published by W. H. Freeman

ISBN 10: 1464125260

ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.5 Planes in 3-Space - Exercises - Page 684: 2

Answer

$-x+2y+z=8$

Work Step by Step

$=$ $(x_{0},y_{0},z_{0})=(3,1,9)$ Equation of the plane in scalar form is $a(x-x_{0})+b(y-y_{0})+c(z-z_{0})=0$ That is, $-1(x-3)+2(y-1)+1(z-9)=0$ or $-x+3+2y-2+z-9= 0$ or -x+2y+z= 8

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