## Calculus (3rd Edition)

$\langle 9,-4,-11\rangle$
The normal vector of a plane in the form of: $ax+by+cz=d$ is given as: $\vec n=\langle a,b,c\rangle$ Therefore, the normal vector of $9x-4y-11z=2$ is $\vec n=\langle 9,-4,-11\rangle$