$\langle 9,-4,-11\rangle $
Work Step by Step
The normal vector of a plane in the form of: $ax+by+cz=d $ is given as: $\vec n=\langle a,b,c\rangle $ Therefore, the normal vector of $9x-4y-11z=2$ is $\vec n=\langle 9,-4,-11\rangle $
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