Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.3 Dot Product and the Angle Between Two Vectors - Exercises - Page 667: 52

Answer

(a) Yes, it is possible. It occurs when the angle between ${\bf{u}}$ and ${\bf{v}}$ is $180^\circ $. (b) ${\bf{u}}$ and ${\bf{v}}$ must be perpendicular vectors.

Work Step by Step

(a) By Eq. (4) of Theorem 3, the component of ${\bf{u}}$ along ${\bf{v}}$ is the vector ${{\bf{u}}_{||{\bf{v}}}}$: ${{\bf{u}}_{||{\bf{v}}}} = \left( {\frac{{{\bf{u}}\cdot{\bf{v}}}}{{{\bf{v}}\cdot{\bf{v}}}}} \right){\bf{v}}$. If the angle between ${\bf{u}}$ and ${\bf{v}}$ is $180^\circ $ then ${\bf{u}}$ and ${\bf{v}}$ are in opposite direction. We have ${{\bf{u}}_{||{\bf{v}}}} = \left( {\frac{{{\bf{u}}\cdot{\bf{v}}}}{{{\bf{v}}\cdot{\bf{v}}}}} \right){\bf{v}} = \left( {\frac{{ - ||{\bf{u}}||||{\bf{v}}||}}{{||{\bf{v}}|{|^2}}}} \right){\bf{v}} = - \frac{{||{\bf{u}}||}}{{||{\bf{v}}||}}{\bf{v}}$ Since ${\bf{u}}$ and ${\bf{v}}$ are in opposite direction, this implies that the component of ${\bf{u}}$ along ${\bf{v}}$ is in ${\bf{u}}$ direction. Now, the component of ${\bf{v}}$ along ${\bf{u}}$ is the vector ${{\bf{v}}_{||{\bf{u}}}}$: ${{\bf{v}}_{||{\bf{u}}}} = \left( {\frac{{{\bf{v}}\cdot{\bf{u}}}}{{{\bf{u}}\cdot{\bf{u}}}}} \right){\bf{u}} = \left( {\frac{{ - ||{\bf{v}}||||{\bf{u}}||}}{{||{\bf{u}}|{|^2}}}} \right){\bf{u}} = - \frac{{||{\bf{v}}||}}{{||{\bf{u}}||}}{\bf{u}}$. We conclude that the component of ${\bf{v}}$ along ${\bf{u}}$ have the opposite sign from the component of ${\bf{u}}$ along ${\bf{v}}$, or vice versa. So, the answer is yes, it is possible. It occurs when the angle between ${\bf{u}}$ and ${\bf{v}}$ is $180^\circ $. (b) We have the component of ${\bf{u}}$ along ${\bf{v}}$ given by ${{\bf{u}}_{||{\bf{v}}}} = \left( {\frac{{{\bf{u}}\cdot{\bf{v}}}}{{{\bf{v}}\cdot{\bf{v}}}}} \right){\bf{v}}$ and the component of ${\bf{v}}$ along ${\bf{u}}$ given by ${{\bf{v}}_{||{\bf{u}}}} = \left( {\frac{{{\bf{v}}\cdot{\bf{u}}}}{{{\bf{u}}\cdot{\bf{u}}}}} \right){\bf{u}}$ If either of these two components is $0$, we must have ${\bf{u}}\cdot{\bf{v}} = {\bf{v}}\cdot{\bf{u}} = 0$ since ${\bf{u}}$ and ${\bf{v}}$ are nonzero vectors. Therefore, ${\bf{u}}$ and ${\bf{v}}$ must be perpendicular vectors.
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