Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.4 Trigonometric Functions - Exercises - Page 30: 30


$$\sin \theta =c, \quad \tan\theta =\frac{c}{\sqrt{1-c^2}}, \quad \csc \theta =\frac{1}{c}.$$

Work Step by Step

By making use of the Pythagorean theorem, we have $$\sin \theta =\frac{c}{1}=c, \quad \tan\theta =\frac{c}{\sqrt{1-c^2}}$$ $$\csc \theta =\frac{1}{\sin\theta}=\frac{1}{c}.$$
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