Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.4 Trigonometric Functions - Exercises - Page 30: 28


$\tan\theta= -2$

Work Step by Step

$\tan^{2}\theta=\sec^{2}\theta-1=5-1=4$ $\tan \theta=±2$ $\cos \theta>0$ (as $\sec\theta>0$) $\sin\theta<0$ (given) $\tan\theta=\frac{\sin\theta}{\cos\theta}=\frac{negative\,value}{positive\,value}=negative\, value$ Therefore, $\tan\theta=-2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.