Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.4 Trigonometric Functions - Exercises - Page 30: 13



Work Step by Step

Since $\sin(x)$ is the y-coordinate on the unit circle As $\sin(x)=\dfrac{\sqrt{3}}{2}$, we search figure 22 for points where the y-coordinate is $\dfrac{\sqrt{3}}{2}$ The two angles on the unit circle where $\sin{x} = \dfrac{\sqrt{3}}{2}$ are $\dfrac{\pi}{3}$ and $\dfrac{2\pi}{3}$ $x= \dfrac{\pi}{3},\dfrac{2\pi}{3}$
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