## Calculus (3rd Edition)

$\dfrac{\pi}{3},\dfrac{2\pi}{3}$
Since $\sin(x)$ is the y-coordinate on the unit circle As $\sin(x)=\dfrac{\sqrt{3}}{2}$, we search figure 22 for points where the y-coordinate is $\dfrac{\sqrt{3}}{2}$ The two angles on the unit circle where $\sin{x} = \dfrac{\sqrt{3}}{2}$ are $\dfrac{\pi}{3}$ and $\dfrac{2\pi}{3}$ $x= \dfrac{\pi}{3},\dfrac{2\pi}{3}$