Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.4 Trigonometric Functions - Exercises - Page 30: 23



Work Step by Step

$\cos^{2}\theta= 1-\sin^{2}\theta=1-\frac{1}{25}=\frac{24}{25}$ $\cos 2\theta=\cos^{2}\theta-\sin^{2}\theta=\frac{24}{25}-\frac{1}{25}=\frac{23}{25}$
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