Answer
The roots of both are reciprocals.
Work Step by Step
Applying the general law of solving a second degree polynomial, we get that the roots are
$\frac{-b \pm \sqrt{b^2 - 4 a c}}{2a}$
and
$\frac{-b \pm \sqrt{b^2 - 4 a c}}{2c}$
(quadratic equation)
That is, the first roots multiplied with $\frac{1}{c}$ equal to the second roots multiplied with $\frac{1}{a}$. Hence, the roots of both are reciprocals.
