## Calculus (3rd Edition)

Applying the general law of solving a second degree polynomial, we get that the roots are $\frac{-b \pm \sqrt{b^2 - 4 a c}}{2a}$ and $\frac{-b \pm \sqrt{b^2 - 4 a c}}{2c}$ (quadratic equation) That is, the first roots multiplied with $\frac{1}{c}$ equal to the second roots multiplied with $\frac{1}{a}$. Hence, the roots of both are reciprocals.