Answer
6 and 4.
Work Step by Step
$x+y=10$
$\implies y=10-x$
Substituting the value of y in
$xy=24$, we have
$x(10-x)=24$ or
$10x-x^{2}=24$
or $x^{2}-10x+24=0$
x=$\frac{-b±\sqrt {b^{2}-4ac}}{2a}=\frac{10±\sqrt {100-4\times1\times24}}{2}$
$x=6$ or $x=4$
If x is 6 y is (10-6)=4.
If x is 4, y is 6.
