Answer
a) x=$\frac{-1}{4}$ ; 1
b) x = 1 ± $\sqrt 2$
Work Step by Step
a) f(x) = 4$x^{2}$ - 3x - 1
(4x+1)(x-1)=0
4x+1 = 0 ; x-1 = 0
x=$\frac{-1}{4}$ ; 1
b) f(x) = $x^{2}$ - 2x - 1
$\frac{-(-2)±\sqrt(-2)^{2}-(4*1*-1)}{2*1}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 1 - Precalculus Review - 1.2 Linear and Quadratic Functions - Exercises - Page 19: 35
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