Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.2 Linear and Quadratic Functions - Exercises - Page 19: 37


$ y=0$

Work Step by Step

Given $$ y=x^{2}-6 x+9$$ So, we have \begin{aligned} y&=x^{2}-6 x+9\\ &=(x-3)(x-3)\\ &=(x-3)^2 \\ \end{aligned} The smallest value for a square power is zero. So, we see that $ y=0$ is the minimum, when $ x=3$.
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