Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.6 Exercises - Page 634: 61

Answer

Converges

Work Step by Step

Here, we have the given series $\Sigma_{n=1}^{\infty} \dfrac{\cos (n)}{3^n}$ Next, we will use the direct comparison test for the given series to check whether it is convergent or divergent. Let us consider that $a_n=\dfrac{\cos (n)}{3^n}$ and $b_n=\dfrac{1}{3^n}$. This implies that $a_n \leq b_n$ From the above series, we can see that the series $b_n$ shows a geometric series with common ratio $r=\dfrac{1}{3} \implies \dfrac{1}{3} \lt 1$. Hence, we can conclude that the given series converges by the direct comparison test
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