Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.6 Exercises - Page 634: 43

Answer

Diverges

Work Step by Step

Here, we have $|a_n|=\Sigma_{n=1}^{\infty}(2\sqrt[n] n+1)^n$ Root Test states that when $\Sigma a_n$ is an infinite series with positive terms and, then $r=\lim\limits_{n \to \infty}\sqrt[n] |a_n|$ a) When $0 \leq r \lt 1$, the series converges. (b) When $r \gt 1$, or, $\infty$, so the series diverges. (c) When $r=1$, the ratio test is inconclusive. Now, $r=\lim\limits_{n \to \infty}\sqrt[n] {(2\sqrt[n] n+1)^n}\\=\lim\limits_{n \to \infty} 2\sqrt[n] n+1 \\=\lim\limits_{n \to \infty} 2 n^{1/n}+1\\=3 \gt 1$ Therefore, the given series diverges by the root test.
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