Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.6 Exercises - Page 634: 58

Answer

Converges

Work Step by Step

Here, we have the given series $\Sigma_{n=1}^{\infty} \dfrac{10}{3 \sqrt{n^3}}$ Re-write the above series: $\Sigma_{n=1}^{\infty} \dfrac{10}{3 \sqrt{n^3}}=\Sigma_{n=1}^{\infty} \dfrac{10}{3n^{3/2}}$ From the above series, we can see that the series shows a p-series with $p=\dfrac{3}{2} \implies \dfrac{3}{2} \gt 1$. Hence, we can conclude that the given series converges by p-series test.
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