Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.6 Exercises - Page 634: 78

Answer

Converges

Work Step by Step

Here, we are given that $a_1=2; a_{n+1}=\dfrac{2n+1}{5n-4} a_n$ Thus, $\dfrac{a_{n+1}}{a_n}=\dfrac{2n+1}{5n-4}$ Next, we have: $\lim\limits_{n \to \infty}|\dfrac{a_{n+1}}{a_n}|=\lim\limits_{n \to \infty} \dfrac{2n+1}{5n-4}=\dfrac{2}{5} \lt 1$ Hence, we can conclude that the given series converges.
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