Answer
$${\text{False}}$$
Work Step by Step
$$\eqalign{
& {\text{False, we can use a substitution to set the integrand to a integration}} \cr
& {\text{formula}}{\text{.}} \cr
& {\text{Example}} \cr
& \int {\frac{{{e^x}}}{{1 - \tan {e^x}}}} dx \cr
& {\text{Is we set }}u = {e^x},{\text{ }}du = {e^x}dx \cr
& \int {\frac{{{e^x}}}{{1 - \tan {e^x}}}} dx = \int {\frac{{du}}{{1 - \tan u}}} \cr
& {\text{Now we can apply formula 72}} \cr
& \int {\frac{1}{{1 \pm \tan u}} = \frac{1}{2}\left( {u \pm \ln \left| {\cos u \pm \sin u} \right|} \right) + C} \cr} $$
