Answer
$$V=\frac{\pi}{4}$$
Work Step by Step
$V=\pi\int _0^1 (y^{\frac{3}{2}})^2 dy$
$V=\pi \int_0^1(y^3)dy$
$V=\pi[\frac{y^4}{4}]_0^1$
$V=\pi(\frac{1^4}{4}-\frac{0^4}{4})$
$V=\pi(\frac{1}{4}-0)$
$$V=\frac{\pi}{4}$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 7 - Applications of Integration - 7.2 Exercises - Page 453: 9
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