## Calculus 10th Edition

$$V=\frac{15}{2}\pi$$
r=$\sqrt x$ $V=\pi\int\limits_1^4(\sqrt x)^2 dx$ $V=\pi\int\limits_1^4(x)dx$ $V=\pi\frac{x^2}{2}│_1^4$ $V=\pi (\frac{4^2}{2}-\frac{1^2}{2})$ $V=\pi(\frac{16}{2}-\frac{1}{2})$ $V=\frac{15}{2}\pi$