Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.2 Exercises - Page 453: 10

Answer

$\frac{153\pi}{5}$

Work Step by Step

Setup the integration using disk method about the y-axis $\pi \int_1^4 (-y^2 +4y)^2dy$ $\pi \int_1^4 (y^4 -8y^3 +16y^2)dy$, Integrate $\pi [\frac{1}{5}y^5 -2y^4 + \frac{16}{3}y^3]_1^4$, Evaluate the definite integral $\pi [(\frac{1024}{5} -512 + \frac{1024}{3}) - (\frac{1}{5} -2 +\frac{16}{3})]$, Simplify, or use your calculator to get a decimal approximation $\approx 96.084$ or $\frac{153\pi}{5}$
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