Answer
$$V=8\pi$$
Work Step by Step
$V=\pi \int_0^4 (\sqrt y)^2 dy$
$V=\pi \int_0^4 (y) dy$
$V=\pi[\frac{y^2}{2}]_0^4$
$V=\pi(\frac{4^2}{2}-\frac{0^2}{2})$
$V=\pi(8-0)$
$V=8\pi$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 7 - Applications of Integration - 7.2 Exercises - Page 453: 7
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