Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.2 Exercises: 7

Answer

$$V=8\pi$$

Work Step by Step

$V=\pi \int_0^4 (\sqrt y)^2 dy$ $V=\pi \int_0^4 (y) dy$ $V=\pi[\frac{y^2}{2}]_0^4$ $V=\pi(\frac{4^2}{2}-\frac{0^2}{2})$ $V=\pi(8-0)$ $V=8\pi$
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