Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.3 Exercises - Page 421: 32

Answer

$${x^2} + {y^2} = 2C$$

Work Step by Step

$$\eqalign{ & \frac{{dy}}{{dx}} = - \frac{x}{y} \cr & {\text{Separate the variables}} \cr & ydy = - xdx \cr & {\text{Integrate both sides}} \cr & \int {ydy} = - \int {xdx} \cr & \frac{1}{2}{y^2} = - \frac{1}{2}{x^2} + C \cr & {x^2} + {y^2} = 2C \cr & {\text{Graph}} \cr} $$
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