Answer
$$y=\sqrt[3] {3x^3+C}$$
Work Step by Step
We first need to gather the $y$ terms on one side, and our $x$ terms on the other side. The easiest way of doing this is by multiplying both sides by $y^2$. We get
$y^2\frac{dy}{dx}=3x^2$. Integrating both sides with respect to $x$ we get
$\int y^2\frac{dy}{dx}dx=\int 3x^2dx$.
Evaluating this integral we get
$\frac{y^3}{3}=x^3+C$
Therefore
$y^3=3x^3+C$,
and finally we are left with
$y=\sqrt[3] {3x^3+C}$
