Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.2 Exercises - Page 412: 6

Answer

$y^2 = -\frac{1}{3}x^{\frac{3}{2}} +C$

Work Step by Step

$\frac{dy}{dx}= -\frac{\sqrt x}{4y}$, separate the variables Integrate $ \int 4ydy = -\int \sqrt x dx$ $ 2y^2 = -\frac{2}{3} x^{\frac{3}{2}} +C$ divide by two $y^2 = -\frac{1}{3} x^{\frac{3}{2}} +C$
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