Answer
$y^2 = -\frac{1}{3}x^{\frac{3}{2}} +C$
Work Step by Step
$\frac{dy}{dx}= -\frac{\sqrt x}{4y}$, separate the variables
Integrate
$ \int 4ydy = -\int \sqrt x dx$
$ 2y^2 = -\frac{2}{3} x^{\frac{3}{2}} +C$
divide by two
$y^2 = -\frac{1}{3} x^{\frac{3}{2}} +C$