Answer
Q=-$\frac{k}{t}$+C
Work Step by Step
$\frac{dQ}{dt}=\frac{k}{t^{2}}$
$\int$$\frac{dQ}{dt}$=$\int$$\frac{k}{t^{2}}$dt
$\int$dQ=-$\frac{k}{t}$+C
Q=-$\frac{k}{t}$+C
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - 6.2 Exercises - Page 412: 11
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