Answer
$y=\frac{1}{4}t^2 +10$
Work Step by Step
$\frac{dy}{dt}=\frac{1}{2}t$
$y=\int\frac{1}{2}t$
$y=\frac{1}{4}t^2 +C$
Using given coordinates, substitute 0 in for t and 10 in for y and solve for C
$10=\frac{1}{4}(0)^2 +C$
$10=C$
$y=\frac{1}{4}t^2 +10$
