Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.2 Exercises - Page 412: 21

Answer

$y= \frac{1}{2} e^{\frac{\ln 10}{5}t}$

Work Step by Step

Use the two given points $(0,\frac{1}{2})$, and $(5,5)$ And the exponential function $y=Ce^{kt} $ Find C $\frac{1}{2} = Ce^0 $ $ C=\frac{1}{2}$ $y=\frac{1}{2}e^{kt}$ Plug in (5,5) $5=\frac{1}{2}e^{5t}$ $\ln {10} = 5t$ $t=\frac{\ln {10}}{5}$ $y= \frac{1}{2} e^{\frac{\ln 10}{5}t}$
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