Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.3 Exercises - Page 345: 87

Answer

$k=\frac{1}{4}$

Work Step by Step

$f^{-1}(3) =-2 ⇒ f(-2) =3 $ $⇒ k(2-(-2)-(-2)^3) = 3$ $⇒12k = 3$ or $k=\frac{1}{4}$
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