Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.3 Exercises - Page 345: 82

Answer

$ \frac{x-3}{2}$

Work Step by Step

To find $(f\circ g)^{-1}$ we can either calculate $fog$ and find its inverse or we can use the relation: $(f\circ g)^{-1} = g^{-1}of^{-1}$ Let's do it by the first method. First, we calculate $(g\circ f)(x) = g(f(x)) = g(x+4) = 2(x+4)-5 = 2x+3$ To find the inverse of f(x), we replace $f(x)$ by $x$ and $ x$ by $ f^{-1}(x)$ and solve for $ f^{-1}(x)$. So, $x = 2(g\circ f)^{-1}(x)+3 $ or $(g\circ f)^{-1}(x) = \frac{x-3}{2}$
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