Answer
$y'=sec(x)$
Work Step by Step
$y= ln|sec(x)+tan(x)|$
$y’=\frac{(sec(x)tan(x))+(sec(x)^2}{sec(x)+tan(x)}$
$=\frac{sec(x)(sec(x)+tan(x))}{sec(x)+tan(x)}$
$=sec(x)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises - Page 325: 64
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