Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises: 62

Answer

$y'=-\cot(x)$

Work Step by Step

$y=ln|csc(x)|$ $\frac{d}{dx}csc(x)=-(csc(x)cot(x))1$ $\frac{d}{dx}ln|x|=\frac{1}{x}$ $\frac{d}{dx}ln|csc(x)|=-\frac{csc(x)cot(x)}{csc(x)}$ $=\boxed{-\cot(x)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.