Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.1 Exercises - Page 325: 28

Answer

$-1$

Work Step by Step

$\frac{1}{e}$ becomes $e^{-1}$ through exponent rules. So, the logarithm becomes $ln(e^{-1})$. Use the rule that $log(x^{n})=nlog(x)$ to simplify the logarithm to $-ln(e).$ Finally, use the fact that $ln(e)=1$ to finally simplify the logarithm to $-1$.
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