## Calculus 10th Edition

domain$: x>0.$ (please see graph (blue) below) .
1. Start by sketching $f_{1}(x)=\ln x$ 2. $f_{2}=-f_{1}(x)=-\ln x$ (reflect $f_{1}$ over the x-axis) 3. $f(x)=2f_{2}(x)=-2\ln x$ (vertically stretch $f_{2}$, factor 2) domain$: x>0.$