Answer
domain$: x>0.$
(please see graph (blue) below)
.
Work Step by Step
1. Start by sketching $f_{1}(x)=\ln x$
2. $f_{2}=-f_{1}(x)=-\ln x$
(reflect $f_{1}$ over the x-axis)
3. $f(x)=2f_{2}(x)=-2\ln x$
(vertically stretch $f_{2}$, factor 2)
domain$: x>0.$
