Answer
$dy=-.04$
$Δy=-.0394$
Work Step by Step
$y=x^{4}+1,x=−1,Δx=dx=.01 $
$y′=4x^{3}$
$dy=f′(x)×dx=4(-1)^{3}\times .01=-.04$
$Δy=f(x+Δx)−f(x)=f(-1+.01)−f(-1)=((-.99)^{4}+1)-((-1)^{4}+1)=1.9606-2=-.0394$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.9 Exercises - Page 236: 9
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