Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.9 Exercises: 14

Answer

$dy=-2\csc(2x)\cot(2x)dx$

Work Step by Step

$y=csc2x$ $\frac{dy}{dx}=-csc(2x)cot(2x)\times2$ (derivative of cscx, chain rule) $dy=-2csc(2x)cot(2x)\times dx$
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