Answer
$\Delta y= -0.322$
$dy= -0.32$
Work Step by Step
$\Delta y=f(x+\Delta x)-f(x)=$
$ f(2+0.01)-f(2)=$$ (2-2.01^{4})-(2-2^{4})=$$-14.322-(-14)= -0.322$
$dy=( \frac{dy}{dx})\Delta x=-4x^{3}\times\Delta x=$$ -4\times2^{3}\times0.01= -0.32$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.9 Exercises - Page 236: 10
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