Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.9 Exercises - Page 236: 15

Answer

$\frac{-3}{(2x-1)^{2}}dx$

Work Step by Step

$y=\frac{x+1}{2x-1}$ Using quotient rule to find $\frac{dy}{dx}$, we have $\frac{dy}{dx}= \frac{1(2x-1)-(x+1)2}{(2x-1)^{2}}= \frac{-3}{(2x-1)^{2}}$ Then, $dy= \frac{-3}{(2x-1)^{2}}dx$
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