Answer
$gradf(2,1)=3i+10j$
Work Step by Step
To find the gradient of $f(x,y)$ denoted $gradf(x,y)$ we use the formula:
$gradf(x,y)=f_{x}(x,y)i+f_{y}(x,y)j$
Note that $f_{x}(x,y)$ and $f_{y}(x,y)$ are partial derivates of the function with respect to $x$ and $y$, respectfully.
$f(x,y)=3x+5y^2+1$
$gradf(x,y)=3i+10yj$
Substituting in the point $(2,1)$ we have
$gradf(2,1)=3i+10(1)j$
$gradf(2,1)=3i+10j$
