Answer
$$\eqalign{
& \left( {\bf{a}} \right){{\bf{w}}_1} = \frac{5}{2}{\bf{i}} + \frac{1}{2}{\bf{j}} \cr
& \left( {\bf{b}} \right){{\bf{w}}_2} = - \frac{1}{2}{\bf{i}} + \frac{5}{2}{\bf{j}} \cr} $$
Work Step by Step
$$\eqalign{
& {\text{Let the vectors be }}{\bf{u}} = 2{\bf{i}} + 3{\bf{j}},{\text{ }}{\bf{v}} = 5{\bf{i}} + {\bf{j}} \cr
& \left( {\bf{a}} \right){\text{ Let }}{{\bf{w}}_1} = {\text{pro}}{{\text{j}}_{\bf{v}}}{\bf{u}} = \left( {\frac{{{\bf{u}} \cdot {\bf{v}}}}{{{{\left\| {\bf{v}} \right\|}^2}}}} \right){\bf{v}} \cr
& {{\bf{w}}_1} = \left( {\frac{{\left( {2{\bf{i}} + 3{\bf{j}}} \right) \cdot \left( {5{\bf{i}} + {\bf{j}}} \right)}}{{{{\left\| {\left( {5{\bf{i}} + {\bf{j}}} \right)} \right\|}^2}}}} \right)\left( {5{\bf{i}} + {\bf{j}}} \right) \cr
& {{\bf{w}}_1} = \left( {\frac{{10 + 3}}{{25 + 1}}} \right)\left( {5{\bf{i}} + {\bf{j}}} \right) \cr
& {{\bf{w}}_1} = \frac{1}{2}\left( {5{\bf{i}} + {\bf{j}}} \right) \cr
& {{\bf{w}}_1} = \frac{5}{2}{\bf{i}} + \frac{1}{2}{\bf{j}} \cr
& \cr
& \left( {\bf{b}} \right){\text{From the Definitions of Projection and Vector Components}} \cr
& {{\bf{w}}_2} = {\bf{u}} - {{\bf{w}}_1}{\text{ is called the }}{\bf{vector}}{\text{ }}{\bf{component}}{\text{ }}{\bf{of}}{\text{ }}{\bf{u}}{\text{ }}{\bf{orthogonal}} \cr
& {\bf{to}}{\text{ }}{\bf{v}}. \cr
& {{\bf{w}}_2} = \left( {2{\bf{i}} + 3{\bf{j}}} \right) - \left( {\frac{5}{2}{\bf{i}} + \frac{1}{2}{\bf{j}}} \right) \cr
& {{\bf{w}}_2} = - \frac{1}{2}{\bf{i}} + \frac{5}{2}{\bf{j}} \cr} $$
