Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.3 Exercises - Page 773: 11

Answer

$1.713$ rad = $98.13^\circ$

Work Step by Step

$\mathbf{u}=3\mathbf{i}+\mathbf{j}$ and $\mathbf{v}=-2\mathbf{i}+4\mathbf{j}$ $\mathbf{u}\cdot\mathbf{v}=3\times(-2)+1\times4=-6+4=-2$ $\|\mathbf{u}\|=\sqrt{3^2+1^2}=\sqrt{10}$ and $\|\mathbf{v}\|=\sqrt{(-2)^2+4^2}=\sqrt{20}=2\sqrt{5}$ ${\theta}=\cos^{-1}\frac{\mathbf{u}\cdot\mathbf{v}}{\|\mathbf{u}\|\|\mathbf{v}\|}=\cos^{-1}\frac{-2}{2\sqrt{10}\sqrt{5}}=\cos^{-1}{-\frac{\sqrt{2}}{10}}=1.713$ rad = $98.13^\circ$
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