Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.2 Exercises - Page 764: 77

Answer

Along direction of $v$: $\frac{1}{3}<2,-1,2>$ Opposite direction of $v$: $-\frac{1}{3}<2,-1,2>$

Work Step by Step

$\mathbf{v}=<2,-1,2>$ $\|\mathbf{v}\|=\sqrt{4+1+4}=3$ Unit Vector in the direction of $\mathbf{v}$: $\frac{1}{3}<2,-1,2>$ Unit Vector in the opposite direction of $\mathbf{v}$: $-\frac{1}{3}<2,-1,2>$
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