Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.2 Exercises - Page 764: 58

Answer

$${\text{ }}{\bf{z}} = \left\langle { - 3,4,20} \right\rangle $$

Work Step by Step

$$\eqalign{ & {\text{Let }}{\bf{u}} = \left\langle {1,2,3} \right\rangle ,{\text{ }}{\bf{v}} = \left\langle {2,2, - 1} \right\rangle ,{\text{ }}{\bf{w}} = \left\langle {4,0, - 4} \right\rangle \cr & {\text{Find }}{\bf{z}} = 5{\bf{u}} - 3{\bf{v}} - \frac{1}{2}{\bf{w}} \cr & {\text{ }}{\bf{z}} = 5\left\langle {1,2,3} \right\rangle - 3\left\langle {2,2, - 1} \right\rangle - \frac{1}{2}\left\langle {4,0, - 4} \right\rangle \cr & {\text{Solve and simplify}} \cr & {\text{ }}{\bf{z}} = \left\langle {5,10,15} \right\rangle - \left\langle {6,6, - 3} \right\rangle - \left\langle {2,0, - 2} \right\rangle \cr & {\text{ }}{\bf{z}} = \left\langle {5 - 6 - 2,10 - 6 - 0,15 + 3 + 2} \right\rangle \cr & {\text{ }}{\bf{z}} = \left\langle { - 3,4,20} \right\rangle \cr} $$
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