Chapter 11 - Vectors and the Geometry of Space - 11.2 Exercises - Page 764: 54

$(1,\frac{4}{3},3)$

Vector: $<1,-\frac{2}{3},\frac{1}{2}>$ Initial Point: $(0,2,\frac{5}{2})$ Terminal Point-Initial Point=Vector Components, and therefore Vector Components+Initial Point=Terminal Point $(1,-\frac{2}{3},\frac{1}{2})+(0,2,\frac{5}{2})=(1,\frac{4}{3},3)$