Answer
$\frac{1}{\sqrt{38}}(1,-1,6)$
Work Step by Step
Initial: $(3,2,0)$ Terminal: $(4,1,6)$.
Component Form: $(4-3,1-2,6-0)=(1,-1,6)$
Magnitude: $\sqrt{1^2+(-1)^2+6^2}=\sqrt{38}$
Unit Vector: $\frac{1}{\sqrt{38}}(1,-1,6)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 11 - Vectors and the Geometry of Space - 11.2 Exercises - Page 764: 49
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